I'm wondering whether henry's law constant for CO2 in NaOH solution is equal to CO2 in water or not. If not, could anyone tell me where I can find this constant for CO2 in 0.3 M NaOH solution at 30 oC? or any formula to calculate?
I believe Henry's constant remains same as that of pure water. Of course ionic equilibrium in liquid phase is affected by dissolved NaOH.
For CO2 in water at 30 oC, H=1860 atm/mole fraction (Foust, Wenzel,"Principles of Unit Operations", Wiley, 1960, Pco2=H*xco2).
For dissolved CO2, ionic equilibrium can be presented (in 3 equations) as
CO2+H2O = HCO3
-+H
+ (pKa=6.37 at 25 oC)
HCO3
-+H2O = CO3
2-+H
+ (pKa=10.25 at 25 oC)
H2O = H
++ OH
- (water dissociation, pK=14 at 25 oC)
For first two equations see the reference "Carbondioxide in waterequilibrium" in
http://www.thuisexperimenteren.nl, or find it by googling "Henry constant CO2"; the reference gives general help on this issue.
Consequently four equations (including that of Henry's constant) have to be solved, considering what is variable and what remains constant. E.g. if NaOH concentration remains constant at 0.3 M, the reference indicates practically only CO3
2- in liquid phase (thus practically zero CO2 in Gas phase), when equilibrium is reached.
Edited by kkala, 04 July 2010 - 05:22 AM.