Jump to content



Featured Articles

Check out the latest featured articles.

File Library

Check out the latest downloads available in the File Library.

New Article

Product Viscosity vs. Shear

Featured File

Vertical Tank Selection

New Blog Entry

Low Flow in Pipes- posted in Ankur's blog

Negative Pressure Drop & Settling Velocity In Sedimentation


This topic has been archived. This means that you cannot reply to this topic.
8 replies to this topic
Share this topic:
| More

#1 polipo

polipo

    Veteran Member

  • Members
  • 41 posts

Posted 23 July 2010 - 09:21 PM

Hi there,

I've done the experiment of fluid flow in pipe and sedimentation. First, I wonder why there is negative pressure drop in sudden expansion. Is it possible that due to the diameter gets larger, and The pressure in the bigger pipe is higher than that of smaller one, so the pressure drop becomes negative? Does this make sense? Moreover, negative pressure drop also existed in orifice meter and venturi meter as well. If so, why is the pressure
proportional to the diameter of the pipe?

For sedimentation, Posted Image I'm unsure that settleing velocity at t1 is (z1-z0)/t1 or (z1-zi)/t1 or (zi-z1)/t1.

Thank you for your assistance.

#2 katmar

katmar

    Gold Member

  • ChE Plus Subscriber
  • 687 posts

Posted 24 July 2010 - 01:48 AM

To understand the pressure increase through a sudden expansion (or a gradual expansion) you need to revise your notes on the Bernoulli Equation. The Bernoulli Equation is a statement of conservation of energy, explaining how kinetic energy is converted to pressure energy as the velocity decreases. The actual pressure increase is less than that predicted by Bernoulli, and this non-ideality is calculated using the k-value for the particular fitting e.g. sudden expansion, pipe reducer or conical section.

If you define the settling velocity as dz/dt at any t, then the slope at t would be (zi-z1)/t1.

#3 polipo

polipo

    Veteran Member

  • Members
  • 41 posts

Posted 25 July 2010 - 02:51 AM

If I change z1 to any other point, will zi change? Or it will be constant in any cases?

One more thing about the concentration. Is the formula: concentration at any time = (initial concentration)(z0)/zi correct? I'm unsure because my results were weird.

Thank you again

#4 katmar

katmar

    Gold Member

  • ChE Plus Subscriber
  • 687 posts

Posted 25 July 2010 - 01:02 PM

zi is the tangent line and z1 is the point of contact between the tangent and the curve. They will both change as t changes. I don't know about the concentration.

#5 polipo

polipo

    Veteran Member

  • Members
  • 41 posts

Posted 26 July 2010 - 06:28 AM

That's fine. Thank you, though.

I still have further questions. Does the concentration affect the settling velocity? Or only particle size that influences on settling velocity?

My result showed about the same settling velocity no matter what concentration it is.

#6 Dacs

Dacs

    Gold Member

  • Members
  • 457 posts

Posted 26 July 2010 - 08:19 PM

That's fine. Thank you, though.

I still have further questions. Does the concentration affect the settling velocity? Or only particle size that influences on settling velocity?

My result showed about the same settling velocity no matter what concentration it is.

This is way back college but I believe that in sedimentation, you have to consider the regime where you based your model on.

At first, the particles are far apart that you can assume that the particles are floating freely.

But as the sediments condense to form a layer, I believe the regime to model it is different since you also have to consider the neighboring particles.

#7 polipo

polipo

    Veteran Member

  • Members
  • 41 posts

Posted 26 July 2010 - 09:08 PM

This is way back college but I believe that in sedimentation, you have to consider the regime where you based your model on.

At first, the particles are far apart that you can assume that the particles are floating freely.

But as the sediments condense to form a layer, I believe the regime to model it is different since you also have to consider the neighboring particles.


Sorry I don't understand your point. Could you please clarify more? I really have problem with sedimentation but I've already tried to research.
By the way, I actually mean the settling velocity in the constant period.

Edited by polipo, 26 July 2010 - 09:15 PM.


#8 Dacs

Dacs

    Gold Member

  • Members
  • 457 posts

Posted 27 July 2010 - 03:51 AM


This is way back college but I believe that in sedimentation, you have to consider the regime where you based your model on.

At first, the particles are far apart that you can assume that the particles are floating freely.

But as the sediments condense to form a layer, I believe the regime to model it is different since you also have to consider the neighboring particles.


Sorry I don't understand your point. Could you please clarify more? I really have problem with sedimentation but I've already tried to research.
By the way, I actually mean the settling velocity in the constant period.

At the initial stage of sedimentation the sediments are scattered all around. So you can say that at this point, the particulates fall freely on their own against the liquid without any intervention from other particulates.

I believe this is the "constant" rate regime.

But at some point, the sedimentation rate will be affected by the neighboring particulates. I think this is the "hindered settling" point.

I'm just pulling it out of what I've learned back in college so my knowledge is rusty at best.

#9 polipo

polipo

    Veteran Member

  • Members
  • 41 posts

Posted 27 July 2010 - 05:15 AM

Thank you a lot. You did save me from this lab. :)




Similar Topics