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Plate Heat Exchanger Viscosity At Wall Example
Started by Guest_stuman_*, Jul 09 2011 12:55 AM
5 replies to this topic
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#1
Guest_stuman_*
Posted 09 July 2011 - 12:55 AM
Hi, I have been trying for ages to calculate the heat flow within gasketed plate heat exchangers.
Using the nusselt equation Nu=a*Re^b*Pr^c*(nu/nu_wall)^0.14, I have come extremely close to calculating a balanced heat flow for heat exchnagers with known values of a,b,c. Throughout all my attempts I have not been able to calculate the Sieder tate viscosity correction coefficient ( nu/nu_wall) as I am unable to determine nu_wall.
There are no examples for this calculation based on coutner current flow through a gasketed plate heat exchanger.
What follows is for an Alfa laval M10B PHE with type L plates ( as outputted from the official alfa laval calculation software )
1 pass of 25 L type channels
effective area = 11.76 m2
Hot flow = 95,000 kg/hr, temp in= 90 C, temp out = 65 C
Cold flow = 50,000 kg/hr, temp in = 12 C, temp out = 59.4 C
Heat transfer hot = 20,469 W/m2K
Heat transfer Cold = 10,259 W/m2K
Overall heat transfer = 5,647 W/m2K
Temperature at wall for the hot side is given as 79.2 C
Temperature at wall on the cold side is given as 39 C.
They ( alfa laval ) seem to use these temps to back calculate the viscosity at wall.
Is anyone able to show me how to calculate these 2 temperatures?
Thanks, Stuman
Using the nusselt equation Nu=a*Re^b*Pr^c*(nu/nu_wall)^0.14, I have come extremely close to calculating a balanced heat flow for heat exchnagers with known values of a,b,c. Throughout all my attempts I have not been able to calculate the Sieder tate viscosity correction coefficient ( nu/nu_wall) as I am unable to determine nu_wall.
There are no examples for this calculation based on coutner current flow through a gasketed plate heat exchanger.
What follows is for an Alfa laval M10B PHE with type L plates ( as outputted from the official alfa laval calculation software )
1 pass of 25 L type channels
effective area = 11.76 m2
Hot flow = 95,000 kg/hr, temp in= 90 C, temp out = 65 C
Cold flow = 50,000 kg/hr, temp in = 12 C, temp out = 59.4 C
Heat transfer hot = 20,469 W/m2K
Heat transfer Cold = 10,259 W/m2K
Overall heat transfer = 5,647 W/m2K
Temperature at wall for the hot side is given as 79.2 C
Temperature at wall on the cold side is given as 39 C.
They ( alfa laval ) seem to use these temps to back calculate the viscosity at wall.
Is anyone able to show me how to calculate these 2 temperatures?
Thanks, Stuman
#2
Posted 09 July 2011 - 01:48 AM
The method should be the same than for a Shell and tube HX , error and trial .
Viscosity correction factor
The viscosity correction factor will normally only be significant for viscous liquids.
To apply the correction an estimate of the wall temperature is needed. This can be
made by first calculating the coefficient without the correction and using the following
relationship to estimate the wall temperature:
hitw t D UT t 12.16
where t D tube-side bulk temperature (mean),
tw D estimated wall temperature,
T D shell-side bulk temperature (mean).
Usually an approximate estimate of the wall temperature is sufficient, but trial-and-error
Hope this helps
Breizh
Viscosity correction factor
The viscosity correction factor will normally only be significant for viscous liquids.
To apply the correction an estimate of the wall temperature is needed. This can be
made by first calculating the coefficient without the correction and using the following
relationship to estimate the wall temperature:
hitw t D UT t 12.16
where t D tube-side bulk temperature (mean),
tw D estimated wall temperature,
T D shell-side bulk temperature (mean).
Usually an approximate estimate of the wall temperature is sufficient, but trial-and-error
Hope this helps
Breizh
#3
Posted 11 July 2011 - 05:42 AM
Hi Stuman
Here is the calculation based on the previous post .
Hope this helps .
Breizh
Here is the calculation based on the previous post .
Hope this helps .
Breizh
#4
Guest_stuman_*
Posted 13 July 2011 - 06:11 AM
Hi Stuman
Here is the calculation based on the previous post .
Hope this helps .
Breizh
Breizh, Thanks, I can see what you have done but unfortunately your results do not match the results from the HX software. In fact, your Twh is 1C hotter than the outlet temperature, the same can nearly be said for Twc.
I apreciate your time,
Stu
#5
Posted 14 July 2011 - 12:32 AM
Hi Stu ,
I found an example in the attached link :
http://www.heattrans...Plate_Calc.html
The methodology applied to your example gave results not far from what you got from your software:
Hope it helps
Breizh
I found an example in the attached link :
http://www.heattrans...Plate_Calc.html
The methodology applied to your example gave results not far from what you got from your software:
Hope it helps
Breizh
Edited by breizh, 14 July 2011 - 12:37 AM.
#6
Guest_stuman_*
Posted 15 July 2011 - 04:29 AM
Hi Stu ,
I found an example in the attached link :
http://www.heattrans...Plate_Calc.html
The methodology applied to your example gave results not far from what you got from your software:
Hope it helps
Breizh
Breizh,
you know, I found this site and example about 1 year ago and it did not really help me much, and then I completely forgot about it. Having another look at it and it seems accurate enough for me to continue my work, and it seems to make sense. I have read the original Sieder tate paper published in 1936, the Colburn AP papers of 1933 and they only cover tubes with a constant wall temperature, which does not apply in my case.
So thanks for helping me try and work this out,
Stu
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