I know what the LMTD is and the AMTD. When can we use AMTD instead of LMTD? Is there a certain kind of heat exchanger that you can use AMTD for?
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Lmtd Vs. Amtd
#1
Posted 14 April 2016 - 01:58 PM
#2
Posted 14 April 2016 - 02:36 PM
What is "AMTD"????
In 53 years of engineering, I never came across this acronym. Please enlighten me.
#3
Posted 14 April 2016 - 02:40 PM
(AMTD) arithmetic mean temperature difference. I am trying to resize a heat exchager and I thought it might be easier if I didn't have to use the log mean temp difference.
#4
Posted 14 April 2016 - 06:17 PM
Heat duty is always done using LMTD. If possible, always use this for double-pipe and 1-1 heat exchangers. Add a correction factor if multipass heat exchanger.
That is, Tlm = ((Thi - Tco) - (Tho-Tci)) / ln((Thi-Tco)/(Tho-Tci))
From my humble understanding of heat transfer, if your Thi-Tco = Tho-Tci (both temperature approach is the same). Your LMTD can be calculated because ln 1 = 0
Just use ((Thi-Tco) + (Tho-Tci))/2 and calculate the heat transfer
ashton46, is this what you mean by AMTD? I never heard this term either.
Choco
#5
Posted 14 April 2016 - 08:33 PM
Try both and convince yourself. And, don't forget the efficiency factor.
Bobby
#6
Posted 15 April 2016 - 12:38 AM
Ashton,
Arithmetic mean temperature difference is used when there is constant temperature difference across heat exchanger at each interval is maintained. If not, you need to use LMTD. LMTD is nothing but you are finding out temperature difference across heat exchanger at fixed intervals and finding out the average of these difference.
LMTD = (Δt1 + Δt2 + .... Δtn)/n
Where Δt1, Δt2... Δtn is temperature difference across heat exchanger at various intervals and 'n' is the number of intervals.
This is mathematically given as LMTD = (ΔT1 - ΔT2)/ln(ΔT1/ΔT2)
Look at the attached sketch where I have shown various profiles for easy understanding.
Attached Files
#7
Posted 15 April 2016 - 02:09 AM
Dear Ashton,
The AMTD is not a term we use regularly for heat exchangers.
Simply put, it is nothing but the arithmetic mean of temperature differences at corresponding points on the shell side and tube side.
AMTD = (Delta T1 + Delta T2 + ...... ) / N,
where n is the number of intervals
But it is not used in any calculations for the heat exchanger duty etc.
The Lmtd is the fundamental parameter, because the LMTD is a measure of the Driving force in the heat exchanger.
The larger the LMTD, the more the heat that is transferred in the exchanger.
It tells us the amount of heat force that exists for exchange to take place, and is defined as :
LMTD = (Delta T1 - Delta T2) / ( Ln (Delta T1) - Ln (Delta T2) )
where 1 and 2 are inlet and outlet cross sections on the heat exchanger, with Delta at each cross section being difference in Tube and shell fluid temperatures.
Regards,
Shantanu
Edited by shantanuk100, 15 April 2016 - 02:11 AM.
#8
Posted 15 April 2016 - 09:17 AM
If you want to see the derivation of The LMTD equation, refer to that old process heat transfer standby: Kern,
#9
Posted 16 April 2016 - 11:56 PM
Ashton
AMTD may occur at special conditions as friends explained.
If you see how the heat balance equation has been derived throughout the Heat Exchanger, you will find that the LMTD is a real term which is obtained from a differential equation. So, you are not allowed to use arithmetic mean of temp. difference to achieve a precise design.
I suggest you to not use it never.
Mahdi
#10
Posted 19 April 2016 - 09:54 AM
Ashton,
In the book: "Examples and Problems to the Course of Unit Operations of Chemical Engineering", by Pavlov K., Romankov A., Noskov A., Mir Publisher, 1979, Moscow, we have:
If the ratio Delta Thigher/ Delta Tless < 2, we can use the following equation with quite accurately:
Delta tm = (Delta Thigher + Delta Tless) / 2
Napo.
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