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Chemical Injection


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#1 abhilashpkurian

abhilashpkurian

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Posted 01 April 2009 - 05:10 AM

Hello,

The problem that I am putting down might be a very simple one. I would request someone, if possible Mr. Art to confirm whether the calculations mentioned below are correct or not.


Query
" Our client mentions that there is a pipe line having a flow of 12000 cu. m/ day of water. They want us to inject a chemical into this pipe line, so that the ppm level of chemical in the pipeline is 5 ppm.
How can one decide the flow (or amount) of the chemical (in lph) that should be added to the pipe line to ensure that the correct ppm is obtained. The relative density of the chemical is 1.2"

Solution
"Flow of water in Pipe line = 12000 cu. m/ day = 500000 lph
Concentration of Chemical to be injected = 5 ppm = 5 mg/lit
Dosage required = 2500000 mg/hr = 2500 g/hr
Relative Density of fluid = 1.2 = 1.2 g/l
Dosage required = 2500 / 1.2 = 2083.3 lph"

Is my calculation correct? Does molecular weight of the chemical play any role in this?

Sorry if I have asked any stupid question.


Thanks and regards,
Abhilash Kurian
Proserv Middle East.

#2 Qalander (Chem)

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Posted 01 April 2009 - 10:46 AM


Dear abhilashpkurian Hello/Good Evening,

Apparently the above seems OK. However:

1) The %age of active ingredient in the chemical per liter and its requirement for injection

2) Its form or state to decide 'mode of injection',any 'pre-dilution' or 'solution' needs

may need consideration

Hopes this helps you in deciding way forward.

Best of luck.

#3 Chem01

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Posted 01 April 2009 - 11:53 AM

@abhilashpkurian,
It should be 208.33 Lph, instead of 2083.3 Lph. Pl. re-check.
Regards,

#4 fallah

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Posted 01 April 2009 - 12:22 PM

QUOTE (abhilashpkurian @ Apr 1 2009, 05:10 AM) <{POST_SNAPBACK}>
Relative Density of fluid = 1.2 = 1.2 g/l
Dosage required = 2500 / 1.2 = 2083.3 lph"


Should be corrected as:
Density of fluid=1200 g/l
Dosage required=2500/1200=2.083 lph

#5 Chem01

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Posted 01 April 2009 - 01:38 PM

Oops,,fallah thanx for correction, it should be 2.08

#6 abhilashpkurian

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Posted 01 April 2009 - 09:10 PM

I knew there was some mistake. Thanks for pointing it out.

#7 Qalander (Chem)

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Posted 01 April 2009 - 10:22 PM

QUOTE (fallah @ Apr 1 2009, 10:22 PM) <{POST_SNAPBACK}>
QUOTE (abhilashpkurian @ Apr 1 2009, 05:10 AM) <{POST_SNAPBACK}>
Relative Density of fluid = 1.2 = 1.2 g/l
Dosage required = 2500 / 1.2 = 2083.3 lph"


Should be corrected as:
Density of fluid=1200 g/l
Dosage required=2500/1200=2.083 lph


Dear fallah,
Thanks very much;I really missed indeed!




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