axl456, I was wrong about the form of the friction factor used in the Churchill equation in the article on Eng-Tips referenced by BigInch. It is indeed the Darcy form. I did not pick up that an "8" had been inserted in the f=8((... equation. In the original article by Churchill there is no "8".
The best example I have come across of the Colebrook or Moody diagram is in the Crane 410 manual. If you are serious about doing pipe calculations it would be well worth your while to purchase a copy. If there is any "standard reference text" in the pipe hydraulics calculation world it is this manual. It is not perfect, but very very useful. You will probably find there is a copy in your department or library. The diagram is on page A-24.
thanks for the reference, am reading now the crane 410 manual
I check the diagram, and i can now perfectly see what you told about the differences between "critical" and "transient" flow..
for what I have read about in other books and what I have seen so far in the crane manual, there are 4 well specified regimens in a fluid inside a pipe, those are:
Laminar flow (Re< 2000)
Critical flow(2000< Re < 4000 according to the a-24 diagram in the crane manual)
Turbulent flow - transient regimen (4000 < Re < 10e4 according to the a-24 diagram in the crane manual)
Turbulent flow - fully turbulent regimen (Re > 10e4 according to the a-24 diagram in the crane manual)
The problem is special with the "critical" flow, because of what i have read (if am not interpreting this wrong), this is a zone where NO constant value of f can be calculated, because the flow is too unstable, behaving like laminar or turbulent depending on several factors (changes in direction, obstruction etc)
In the turbulent flow with transient regimen, the f factor depends on both Reynolds number and relative roughness, and can be calculated with the colebrook equation..
In the fully turbulent flow, it appears as if the flow stop depending on the Reynolds number and depends only on the relative roughness,because the relative roughness lines are almost totally horizontal. This I havent read in any books, is just an observation of the diagram, and a conclusion I made because I have read that the colebrook equation works only on Reynolds number between the lines of smooth pipes and totally turbulent flow on the diagram (McGraw-Hill Piping Handbook 7th edition page B.372)
This of course is contradictory with other observation I have read claiming that the colebrook equation can be used for all Reynolds number above 4000 (I think this is because the % of error is to small)
Well I think that I have stole to much time from you, thanks for all the answer, they have been very very helpful
I actually have many things i would like to ask, sadly I haven't find any teacher in my university that cant help me with all this, but i feel that am being rude asking to much
If you are willing to help me with others question it will be very helpful if not i will understand and move my noobness to another thread or site
Again, thank you very much for helping..
Edited by axl456, 28 January 2010 - 09:57 PM.